交叉字符串

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代码（C++）:

class Solution {
public:
/**
* Determine whether s3 is formed by interleaving of s1 and s2.
* @param s1, s2, s3: As description.
* @return: true of false.
*/
bool isInterleave(string s1, string s2, string s3) {
// write your code here
if (s3.length() != s1.length()+s2.length())
return false;
if (s1.length() == 0)
return s2 == s3;
if (s2.length() == 0)
return s1 == s3;
vector<vector<bool> > dp(s1.length()+1, vector<bool>(s2.length()+1, false));
dp[0][0] = true;
for (int i = 1; i <= s1.length(); i++)
dp[i][0] = dp[i-1][0]&&(s3[i-1] == s1[i-1]);
for (int i = 1; i <= s2.length(); i++)
dp[0][i] = dp[0][i-1]&&(s3[i-1] == s2[i-1]);
for (int i = 1; i <= s1.length(); i++) {
for (int j = 1; j <= s2.length(); j++) {
int t = i+j;
if (s1[i-1] == s3[t-1])
dp[i][j] = dp[i][j]||dp[i-1][j];
if (s2[j-1] == s3[t-1])
dp[i][j] = dp[i][j]||dp[i][j-1];
}
}
return dp[s1.length()][s2.length()];
}
};

交叉字符串

标签：public   write   code   src   c++   whether   leave   class   http   

原文地址：http://www.cnblogs.com/majixian/p/7221828.html