码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode Solutions : Combination Sum I & II

时间:2014-09-02 17:48:05      阅读:244      评论:0      收藏:0      [点我收藏+]

标签:leetcode   java   algorithms   datastructure   np   

Combination Sum 

Given a set of candidate numbers (C) and a target number (T), 
find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:
All numbers (including target) will be positive integers.
Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
The solution set must not contain duplicate combinations.
For example, given candidate set 2,3,6,7 and target 7, 
A solution set is: 
[7] 
[2, 2, 3] 

public class Solution {
    public ArrayList<ArrayList<Integer>> combinationSum(int[] candidates, int target) {
        ArrayList<ArrayList<Integer>> results=new ArrayList<ArrayList<Integer>>();
		if(candidates==null)
			return results;
		Arrays.sort(candidates);
		helper(candidates,0,target,results,new ArrayList<Integer>());
		return results;
    }
	private void helper(int[] candidates,int start,int target,ArrayList<ArrayList<Integer>> results,ArrayList<Integer> temp){
		if(target==0){
			results.add(new ArrayList<Integer>(temp));
			return;
		}
		for(int i=start;i<candidates.length;i++){
			if(candidates[i]<=target){
				temp.add(candidates[i]);
				helper(candidates,i,target-candidates[i],results,temp);
				temp.remove(temp.size()-1);
			}
		}
	}
}

Combination Sum II 

Given a collection of candidate numbers (C) and a target number (T),
 find all unique combinations in C where the candidate numbers sums to T.

Each number in C may only be used once in the combination.

Note:
All numbers (including target) will be positive integers.
Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
The solution set must not contain duplicate combinations.
For example, given candidate set 10,1,2,7,6,1,5 and target 8, 
A solution set is: 
[1, 7] 
[1, 2, 5] 
[2, 6] 
[1, 1, 6] 

public class Solution {
    public ArrayList<ArrayList<Integer>> combinationSum2(int[] num, int target) {
        ArrayList<ArrayList<Integer>> results=new ArrayList<ArrayList<Integer>>();
		if(num==null)
			return results;
		Arrays.sort(num);
		helper(num,0,target,results,new ArrayList<Integer>());
		return results;
    }
	private void helper(int[] candidates,int start,int target, ArrayList<ArrayList<Integer>> results,ArrayList<Integer> temp){
		if(target==0){
			results.add(new ArrayList<Integer>(temp));
			return;
		}
		for(int i=start;i<candidates.length;i++){
			if(i>start&&candidates[i]==candidates[i-1])
				continue;
			if(candidates[i]<=target){
				temp.add(candidates[i]);
				helper(candidates,i+1,target-candidates[i],results,temp);
				temp.remove(temp.size()-1);		
			}			
		}		
	}
}


LeetCode Solutions : Combination Sum I & II

标签:leetcode   java   algorithms   datastructure   np   

原文地址:http://blog.csdn.net/lviiii/article/details/39008797

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!