标签:字典树
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1671
2 3 911 97625999 91125426 5 113 12340 123440 12345 98346
NO YES
题意:
统计是否有相同的前缀!
代码如下:
#include <cstdio>
#include <cstring>
#include <malloc.h>
#include <iostream>
using namespace std;
#define MAXN 10
typedef struct Trie
{
int v;//根据需要变化
Trie *next[MAXN];
//next是表示每层有多少种类的数,如果只是小写字母,则26即可,
//若改为大小写字母,则是52,若再加上数字,则是62了
}Trie;
Trie* root;
void createTrie(char *str)
{
int len = strlen(str);
Trie *p = root, *q;
for(int i = 0; i < len; i++)
{
int id = str[i]-'0';
if(p->next[id] == NULL)
{
q = (Trie *)malloc(sizeof(Trie));
q->v = 1;//初始v==1
for(int j = 0; j < MAXN; j++)
q->next[j] = NULL;
p->next[id] = q;
p = p->next[id];
}
else
{
p->next[id]->v++;
p = p->next[id];
}
}
p->v = -1;//若为结尾,则将v改成-1表示
}
int findTrie(char *str)
{
int len = strlen(str);
Trie *p = root;
for(int i = 0; i < len; i++)
{
int id = str[i]-'0';
p = p->next[id];
if(p == NULL) //若为空集,表示不存以此为前缀的串
return 0;
if(p->v == -1) //字符集中已有串是此串的前缀
return -1;
}
//return p->v;
return -1; //此串是字符集中某串的前缀
}
int dealTrie(Trie* T)
{
//动态字典树,有时会超内存,这是就要记得释放空间了
if(T==NULL)
return 0;
for(int i = 0; i < MAXN; i++)
{
if(T->next[i]!=NULL)
dealTrie(T->next[i]);
}
free(T);
return 0;
}
int main()
{
int t, n;
char str[15];
scanf("%d",&t);
while(t--)
{
int flag = 0;
root = (Trie *)malloc(sizeof(Trie));
for(int i = 0; i < MAXN; i++)
root->next[i] = NULL;
scanf("%d",&n);
for(int i = 0; i < n; i++)
{
scanf("%s",str);
if(findTrie(str) == -1)
{
flag = 1;
continue;
}
createTrie(str);
}
if(flag)
printf("NO\n");
else
printf("YES\n");
dealTrie(root);
}
return 0;
}
标签:字典树
原文地址:http://blog.csdn.net/u012860063/article/details/39007631