标签：eve display return cin line number closed meta set
InputThe input starts with a positive integer P which indicates the number of test cases. Then on the following P lines,each line consists 2 positive integer m and n(0<m,n<2147483648).
OutputFor each input m n, if safe holes exist, you should output "YES", else output "NO" in a single line.
Sample Input
2 1 2 2 2
Sample Output
NO YES
找互质的数
1 #include <iostream> 2 using namespace std; 3 #include<string.h> 4 #include<set> 5 #include<stdio.h> 6 #include<math.h> 7 #include<queue> 8 #include<map> 9 #include<algorithm> 10 #include<cstdio> 11 #include<cmath> 12 #include<cstring> 13 #include <cstdio> 14 #include <cstdlib> 15 int TM(int a,int b) 16 { 17 if(a%b==0) 18 return b; 19 return TM(b,a%b); 20 } 21 int main() 22 { 23 int n,m; 24 int t; 25 cin>>t; 26 while(t--) 27 { 28 cin>>n>>m; 29 if(n==1) 30 { 31 cout<<"NO"<<endl; 32 continue; 33 } 34 if(TM(m,n)!=1) 35 cout<<"YES"<<endl; 36 else 37 cout<<"NO"<<endl; 38 } 39 40 return 0; 41 }
标签：eve display return cin line number closed meta set
原文地址：http://www.cnblogs.com/dulute/p/7272963.html
