标签：odi row neu already sum san otto sed flow
Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321Have you thought about this?Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
If the integer‘s last digit is 0, what should the output be? ie, cases such as 10, 100.
Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?
Throw an exception? Good, but what if throwing an exception is not an option? You would then have to re-design the function (ie, add an extra parameter).
首先推断正负，然后从整数的地位開始循环，转换为新数。PS：没有考虑越界问题。public int reverse(int x) { int flag = 0; if(x < 0){ flag = 1; x = - x; } int y = 0; int remainder; while(x > 0){ remainder = x % 10; x = x/10; y = y * 10 + remainder; } if(flag == 1){ y = -y; } return y; }
标签：odi row neu already sum san otto sed flow
原文地址：http://www.cnblogs.com/brucemengbm/p/7276908.html
