标签:ane ted cal cas printf help const scan lin
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1493 Accepted Submission(s): 594
#include <iostream> #include <algorithm> #include <cstring> #include <cstdio> #include <vector> #include <queue> #include <cstdlib> #include <iomanip> #include <cmath> #include <ctime> #include <map> #include <set> using namespace std; #define lowbit(x) (x&(-x)) #define max(x,y) (x>y?x:y) #define min(x,y) (x<y?x:y) #define MAX 100000000000000000 #define MOD 1000000007 #define pi acos(-1.0) #define ei exp(1) #define PI 3.141592653589793238462 #define ios() ios::sync_with_stdio(false) #define INF 0x3f3f3f3f #define mem(a) (memset(a,0,sizeof(a))) typedef long long ll; int f[70]; int n,m,t; struct Node { double x; double y; }node[55]; struct E { int u; int v; double w; friend bool operator<(const E &a,const E&b) { return a.w<b.w; } }e[3000]; double dist(Node a,Node b) { return (double)sqrt(((a.x-b.x)*(a.x-b.x)*1.0)+((a.y-b.y)*(a.y-b.y)*1.0)); } int find(int x) { return f[x]==x?x:find(f[x]); } double kruskal() { double ans=0.0; int k=1,q=n-1; for(int i=0;i<=n;i++) { f[i]=i; } for(int i=0;i<m;i++) { int u=find(e[i].u); int v=find(e[i].v); if(u!=v) { ans+=e[i].w; if(u<v) f[u]=v; else f[v]=u; k++; if(k==q) break; } } return ans; } int main() { scanf("%d",&t); while(t--) { scanf("%d",&n); for(int i=0;i<n;i++) { scanf("%lf %lf",&node[i].x,&node[i].y); } double ans=1000000.0; for(int k=0;k<n;k++) { m=0; for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { if(i==k || j==k) continue; e[m].u=i; e[m].v=j; e[m++].w=dist(node[i],node[j]); } } sort(e,e+m); ans=min(ans,kruskal()); } printf("%.2f\n",ans); } return 0; }
标签:ane ted cal cas printf help const scan lin
原文地址:http://www.cnblogs.com/shinianhuanniyijuhaojiubujian/p/7281815.html