标签:core until lines tin log ems diagonal with oss
The cows don‘t use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bowling-pin-like triangle like this:
7
3 8
8 1 0
2 7 4 4
4 5 2 6 5
Then the other cows traverse the triangle starting from its tip and moving "down" to one of the two diagonally adjacent cows until the "bottom" row is reached. The cow‘s score is the sum of the numbers of the cows visited along the way. The cow with the highest score wins that frame.
Given a triangle with N (1 <= N <= 350) rows, determine the highest possible sum achievable.Input
Output
Sample Input
5 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5
Sample Output
30
Hint
7The highest score is achievable by traversing the cows as shown above.
*
3 8
*
8 1 0
*
2 7 4 4
*
4 5 2 6 5
1 #include<cstdio> 2 #include<cstring> 3 #include<iostream> 4 #include<algorithm> 5 using namespace std; 6 7 int n; 8 int map[400][400],dp[400][400]; 9 10 void solve() 11 { int ans=0; 12 for(int i=n-2;i>=0;i--) 13 for(int j=0;j<=i;j++) 14 dp[i][j]=max(dp[i+1][j]+map[i+1][j],dp[i+1][j+1]+map[i+1][j+1]); 15 ans=dp[0][0]+map[0][0]; 16 cout<<ans<<endl; 17 } 18 19 int main() 20 { cin>>n; 21 for(int i=0;i<n;i++) 22 for(int j=0;j<i+1;j++) 23 scanf("%d",&map[i][j]); 24 memset(dp,0,sizeof(dp)); 25 26 solve(); 27 }
标签:core until lines tin log ems diagonal with oss
原文地址:http://www.cnblogs.com/zgglj-com/p/7287310.html