标签：方法 衡量 cts ips signed recent can namespace ges
Factstone Benchmark
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2259 Accepted Submission(s): 1277Problem DescriptionAmtel has announced that it will release a 128-bit computer chip by 2010, a 256-bit computer by 2020, and so on, continuing its strategy of doubling the word-size every ten years. (Amtel released a 64-bit computer in 2000, a 32-bit computer in 1990, a 16-bit computer in 1980, an 8-bit computer in 1970, and a 4-bit computer, its first, in 1960.)
Amtel will use a new benchmark - the Factstone - to advertise the vastly improved capacity of its new chips. The Factstone rating is defined to be the largest integer n such that n! can be represented as an unsigned integer in a computer word.
Given a year 1960 ≤ y ≤ 2160, what will be the Factstone rating of Amtel‘s most recently released chip?
There are several test cases. For each test case, there is one line of input containing y. A line containing 0 follows the last test case. For each test case, output a line giving the Factstone rating.Sample Input196019810Sample Output38
题意：××公司是制造computer的，1960年它造的computer是4bit的，之后每10年翻倍；
有一个衡量computer的标准，就是它最大可以存下n!(无符号位)，那么它就是n级；
求x年时该公司的电脑为几级（1960<= x <=2160)；
思路：也是求位数的题目，方法类似hdu1018 链接http://www.cnblogs.com/ISGuXing/p/7301041.html
只不过用log2
这道题打表。
代码：
1 #include<iostream> 2 #include<stdio.h> 3 #include<cmath> 4 #include<algorithm> 5 #include<math.h> 6 using namespace std; 7 int a[350000]; 8 int main(){ 9 double k=0.0; 10 for(int i=1;i<=350000;i++){ 11 k+=log2(i); 12 a[i]=(int)k+1; 13 } 14 int year; 15 while(scanf ("%d",&year)&&year!=0){ 16 int x=(year-1960)/10; 17 int bit=4*(pow(2,x)); 18 int pos=lower_bound(a,a+350000,bit)-a; 19 if(a[pos]>bit){ 20 pos--; 21 } 22 cout<<pos<<endl; 23 } 24 return 0; 25 }
标签：方法 衡量 cts ips signed recent can namespace ges
原文地址：http://www.cnblogs.com/ISGuXing/p/7301064.html
