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7. Reverse Integer 翻转整型

时间:2017-08-10 01:10:18      阅读:138      评论:0      收藏:0      [点我收藏+]

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Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

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Have you thought about this?

Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!

If the integer‘s last digit is 0, what should the output be? ie, cases such as 10, 100.

Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?

For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.


  1. class Solution(object):
  2. def reverse(self, x):
  3. """
  4. :type x: int
  5. :rtype: int
  6. """
  7. b = (x>0) - (x<0)
  8. num = b * int(str(abs(x))[::-1])
  9. if num.bit_length() < 32:
  10. return num
  11. else:
  12. return 0





7. Reverse Integer 翻转整型

标签:self   should   his   not   output   size   its   tty   read   

原文地址:http://www.cnblogs.com/xiejunzhao/p/7333779.html

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