标签:order string ons 不同的 == family start substr height
Given a string, your task is to count how many palindromic substrings in this string.
The substrings with different start indexes or end indexes are counted as different substrings even they consist of same characters.
Example 1:
Input: "abc" Output: 3 Explanation: Three palindromic strings: "a", "b", "c".
Example 2:
Input: "aaa" Output: 6 Explanation: Six palindromic strings: "a", "a", "a", "aa", "aa", "aaa".
Note:
class Solution(object):
def countSubstrings(self, s):
"""
:type s: str
:rtype: int
"""
num = 0
for i in range(0, len(s) + 1):
for j in range(i + 1, len(s) + 1):
sub = s[i:j]
if(sub == sub[::-1]):
num = num + 1
return num
647. Palindromic Substrings 回文子串的数量
标签:order string ons 不同的 == family start substr height
原文地址:http://www.cnblogs.com/xiejunzhao/p/7354950.html