标签:strong 练习 exist lin problem limit tput span java
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 29129 Accepted Submission(s): 12254
1 #include <algorithm> 2 #include <cstdio> 3 4 using namespace std; 5 6 const int N(1000000+5); 7 const int M(10000+626); 8 int l1,l2,a[N],b[N],p[N]; 9 10 inline void Get_next() 11 { 12 for(int j=0,i=2;i<=l2;i++) 13 { 14 if(j>0&&b[i]!=b[j+1]) j=p[j]; 15 if(b[i]==b[j+1]) j++; 16 p[i]=j; 17 } 18 } 19 inline void kmp() 20 { 21 for(int j=0,i=1;i<=l1;i++) 22 { 23 if(j>0&&a[i]!=b[j+1]) j=p[j]; 24 if(a[i]==b[j+1]) j++; 25 if(j==l2) 26 { 27 printf("%d\n",i-j+1); 28 return ; 29 } 30 } 31 puts("-1"); 32 } 33 34 int main() 35 { 36 int t;scanf("%d",&t); 37 for(;t--;) 38 { 39 scanf("%d%d",&l1,&l2); 40 for(int i=1;i<=l1;i++) scanf("%d",a+i); 41 for(int i=1;i<=l2;i++) scanf("%d",b+i); 42 Get_next(); 43 kmp(); 44 } 45 return 0; 46 }
标签:strong 练习 exist lin problem limit tput span java
原文地址:http://www.cnblogs.com/Shy-key/p/7360019.html