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项目 人机猜拳

时间:2017-08-14 21:32:43      阅读:153      评论:0      收藏:0      [点我收藏+]

标签:错误   name   while   amp   dom   选择   ext   and   rgs   

人机猜拳

public class bdqn1 {

    /**
     * @param args
     */
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        String m = "";
        int juese = 1;
        bdqn2 c = new bdqn2();
        bdqn3 b = new bdqn3();
        do {
            System.out.println("******************欢迎进入游戏世界******************");
            System.out.println();
            System.out.println("\t    **************************");
            System.out.println("\t    **     猜拳 ,开始         **");
            System.out.println("\t    **************************");
            System.out.println("\n");
            System.out.println("出拳规则:1 剪刀2石头3布");
            System.out.println("请输入姓名:");
            String name = input.next();
            b.showw();
            System.out.println("开始吗");
            String o = input.next();
            if (o.equals("y")) {
                c.show();
                if (juese == 1) {
                    System.out.println("刘备" + "vs" + name);
                }
                if (juese == 2) {
                    System.out.println("孙权" + "vs" + name);
                }
                if (juese == 3) {
                    System.out.println("曹操" + "vs" + name);
                }
                c.show2();
                System.out.println("下回加油");
            } else {
                System.out.println("还继续吗");
                m = input.next();
            }
        } while (m.equals("y"));
        System.out.println("拜拜");

    }
}
public class bdqn2 {

    Scanner input=new Scanner(System.in);
    String y = "";
    int count=0;
    int a=0;
    int b=0;
     public void show(){
         do{
                int random=(int)(Math.random()*3+1);
                System.out.println("请出拳: 1 剪刀   2石头   3布");
            
         System.out.println("你出拳");
            int number = input.nextInt();
            if(number<=3){
            switch (number) {
            case 1:
                System.out.println("你的出拳是    剪刀");
                break;
            case 2:
                System.out.println("你的出拳是  石头");
                break;
            case 3:
                System.out.println("你的出拳是    布");
                break;
            default:
                System.out.println("错误请重新输入");
            }
            
    if(random==1){
        System.out.println("电脑出:  剪刀");
    }if(random==2){
        System.out.println("电脑出:  石头");
    }if(random==3){
        System.out.println("电脑出:  布");
    }
    if ((number == 1 && random == 1)
            || (number == 2 && random == 2)
            || (number  == 3 && random == 3)) {
        System.out.println("结果:和局真衰");
    } else if ((number  == 1 && random == 3)
            || (number  == 2 && random == 1)
            || (number  == 3 && random == 2)) {
        System.out.println("恭喜你赢了");
        a++;
    } else {
        System.out.println("结果说:你输了真笨");
        b++;
    }
            }else{
                System.out.println("错误 请重新输入");
            }
    System.out.println("继续吗");
    y=input.next();
    count++;
            }while(y.equals("y"));
         System.out.println("************************************");
            
            System.out.println("对战次数"+count);
            
     }
public void show2(){
    System.out.println("你得"+a+"分"+"电脑得"+b+"分");
    
}
}
public class bdqn3 {
    public void showw() {
    
        int juese =0;
        Scanner input = new Scanner(System.in);
        do{
            System.out.println("请选择对方角色 :1:刘备2:孙权3:曹操");
             
             juese = input.nextInt();
            
            
            if(juese==1){
                System.out.println("你选择了刘备对战");
                break;
            }
            if(juese==2){ 
                System.out.println("你选择了孙权对战");
                break;
            }if(juese==3){
                System.out.println("你选择了曹操");
                break;    
            }else{
                System.out.println("错误 请重新选择");
            }
            }while(juese!=1&&juese!=2&&juese!=3);
            

    }

}

 

项目 人机猜拳

标签:错误   name   while   amp   dom   选择   ext   and   rgs   

原文地址:http://www.cnblogs.com/wh1520577322/p/7359819.html

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