标签:cout name space 情况 tarjan ons ini out blog
1 #include<bits/stdc++.h> 2 #define INF 0x7fffffff 3 using namespace std; 4 const int MAXN = 50010;//点数 5 const int MAXM = 100100;//边数 6 struct Edge { 7 int to,next,val; 8 }edge[MAXM]; 9 int head[MAXN],tot,a,b; 10 int Low[MAXN],DFN[MAXN],Stack[MAXN],Belong[MAXN];//Belong数组的值是1~scc 11 int Index,top; int scc;//强连通分量的个数 12 int in[MAXN],out[MAXN],val[MAXN],d[MAXN]; 13 bool Instack[MAXN]; 14 int num[MAXN];//各个强连通分量包含点的个数,数组编号1~scc //num数组不一定需要,结合实际情况 15 int cnt=0,ans=0; 16 void addedge(int u,int v,int w){ 17 edge[tot].to = v; 18 edge[tot].next = head[u]; 19 edge[tot].val=w; 20 head[u] = tot++; 21 } 22 void Tarjan(int u){ 23 int v; 24 Low[u] = DFN[u] = ++Index; 25 Stack[top++] = u; 26 Instack[u] = true; 27 for(int i = head[u];i != -1;i = edge[i].next) { 28 v = edge[i].to; 29 if( !DFN[v] ){ 30 Tarjan(v); 31 if( Low[u] > Low[v] ) 32 Low[u] = Low[v]; 33 } 34 else if(Instack[v] && Low[u] > DFN[v]) 35 Low[u] = DFN[v]; 36 } 37 if(Low[u] == DFN[u]){ 38 scc++; 39 do{ 40 v = Stack[--top]; 41 Instack[v] = false; 42 Belong[v] = scc; 43 num[scc]++; 44 }while( v != u); 45 } 46 } 47 void find_val(int u){ 48 int v; 49 for(int i = head[u];i != -1;i = edge[i].next){ 50 v = edge[i].to; 51 if(Belong[u]==Belong[v]) continue; 52 val[Belong[v]]=min(val[Belong[v]],edge[i].val); 53 //out[Belong[u]]++; 54 } 55 } 56 void solve(int N){ 57 memset(DFN,0,sizeof(DFN)); 58 memset(Instack,false,sizeof(Instack)); 59 memset(num,0,sizeof(num)); 60 Index = scc = top = 0; 61 for(int i=1;i<=N;i++) val[i]=INF; 62 for(int i = 1;i <= N;i++) 63 if(!DFN[i]) 64 Tarjan(i); 65 for(int i=1;i<=N;i++){ 66 // val[Belong[i]]=min(val[Belong[i]],d[i]); 67 find_val(i); 68 } 69 val[Belong[1]]=0; 70 for(int i=1;i<=scc;i++){ 71 ans+=val[i]; 72 } 73 } 74 void init(){ 75 tot = 0; 76 cnt=0,ans=0; 77 memset(head,-1,sizeof(head)); 78 memset(in,0,sizeof(in)); 79 memset(out,0,sizeof(out)); 80 } 81 int main(){ 82 int n,m,u,v,w,T; 83 while(scanf("%d%d",&n,&m)!=EOF){ 84 init(); 85 //for(int i=1;i<=n;i++) scanf("%d",&d[i]); 86 for(int i=1;i<=m;i++){ 87 scanf("%d%d%d",&u,&v,&w); 88 u++,v++; 89 addedge(u,v,w); 90 } 91 solve(n); 92 cout<<ans<<endl; 93 //cout<<cnt<<‘ ‘<<ans<<endl; 94 } 95 return 0; 96 }
标签:cout name space 情况 tarjan ons ini out blog
原文地址:http://www.cnblogs.com/poler/p/7391111.html