HDU2948Geometry Darts(简单计算几何)

  1 #include <map>
  2 #include <set>
  3 #include <stack>
  4 #include <queue>
  5 #include <cmath>
  6 #include <ctime>
  7 #include <vector>
  8 #include <cstdio>
  9 #include <cctype>
 10 #include <cstring>
 11 #include <cstdlib>
 12 #include <iostream>
 13 #include <algorithm>
 14 using namespace std;
 15 #define eps 1e-12
 16 #define MAXN 55
 17 #define INF 1e30
 18 #define mem0(a) memset(a,0, sizeof(a))
 19 #define mem1(a) memset(a,-1,sizeof(a))
 20 double MAX(double a, double b) {return a > b ? a : b;}
 21 double MIn(double a, double b) {return a < b ? a : b;}
 22 typedef long long LL;
 23 /****************************************计算几何头文件**************************************************/
 24 struct Point{
 25     double x,y;
 26     Point(double x=0, double y=0):x(x),y(y){}
 27 };
 28 
 29 struct Polygon
 30 {
 31     Point p[MAXN];
 32     int Size;
 33 };
 34 
 35 struct Circle
 36 {
 37     Point o;
 38     double r;
 39     Circle(){}
 40     Circle(Point _o, double _r):o(_o),r(_r){}
 41 };
 42 
 43 Point operator + (Point A, Point B) {return Point(A.x+B.x, A.y+B.y);}
 44 
 45 Point operator - (Point A, Point B) {return Point(A.x-B.x, A.y-B.y);}
 46 
 47 Point operator * (Point A, double p) {return Point(A.x*p, A.y*p);}
 48 
 49 Point operator / (Point A, double p) {return Point(A.x/p, A.y/p);}
 50 
 51 int dcmp(double x) {
 52     if(fabs(x) < eps) return 0;
 53     else return x < 0 ? -1 : 1;
 54 }
 55 
 56 bool operator == (const Point &A, const Point &B) {
 57     return dcmp(A.x-B.x) == 0 && dcmp(A.y-B.y) == 0;
 58 }
 59 
 60 double Dot(Point A, Point B) { return A.x*B.x + B.y*B.y;}    //点积
 61 
 62 double Length(Point A) { return sqrt(Dot(A,A));}             //向量长度
 63 
 64 double Angle(Point A, Point B) {return acos(Dot(A,B) / Length(A) / Length(B));}//向量夹角
 65 
 66 double cross(Point A, Point B) {return A.x*B.y - A.y*B.x;}
 67 
 68 bool crossed(Point a, Point b, Point c, Point d)//线段ab和cd是否相交
 69 {
 70     if(cross(a-c, d-c)*cross(b-c, d-c)<=0 && cross(c-a, b-a)*cross(d-a, b-a)<=0)
 71     {
 72         return true;
 73     }
 74     return false;
 75 }
 76 
 77 bool isPointOnSegent(Point p, Point s, Point e)//判断点是否在线段se上
 78 {
 79     double d = (p.x-s.x) * (e.x-p.x);
 80     double a = (p.y-s.y) / (p.x-s.x);
 81     double b = (e.y-p.y) / (e.x-p.x);
 82     if(dcmp(d)==1 && dcmp(a-b)==0)return true;
 83     return false;
 84 }
 85 
 86 int isPointInPolygon(Point p, Polygon poly)//判断点是否在多边形以内
 87 {
 88     int w = 0;
 89     int n = poly.Size;
 90     for(int i=0;i<n;i++)
 91     {
 92         if(isPointOnSegent(p, poly.p[i], poly.p[(i+1)%n])) return 1;//点在边上
 93         int k = dcmp(cross(poly.p[(i+1)%n]-poly.p[i], p-poly.p[i]));
 94         int d1 = dcmp(poly.p[i].y - p.y);
 95         int d2 = dcmp(poly.p[(i+1)%n].y - p.y);
 96         if(k > 0 && d1 <= 0 && d2 > 0) w++;
 97         if(k < 0 && d2 <= 0 && d1 > 0) w--;
 98     }
 99     if(w != 0) return 1;
100     return 0;
101 }
102 
103 /****************************************************************************************************/
104 struct R
105 {
106     Point a, b;
107     R(){}
108     R(Point _a, Point _b)
109     {
110         a = _a;
111         b = _b;
112     }
113 }r[1001];
114 struct T
115 {
116     Point a, b, c;
117     T(){}
118     T(Point _a, Point _b, Point _c) {
119         a = _a; b = _b; c = _c;
120     }
121 }t[1001];
122 Circle c[1001];
123 int S, N;
124 int cntC = 0, cntT = 0, cntR = 0;
125 
126 int calc(double x, double y)//计算点(x, y)在图中的多少个图形内部
127 {
128     Point p = Point(x, y);
129     int ans = 0;
130     for(int i=0;i<cntC;i++)
131     {
132         if(Length(p-c[i].o) <= c[i].r) ans ++;
133     }
134     for(int i=0;i<cntT;i++)
135     {
136         if(   cross(t[i].c-t[i].a, p-t[i].a)*cross(t[i].b-t[i].a, p-t[i].a)<=0
137            && cross(t[i].a-t[i].b, p-t[i].b)*cross(t[i].c-t[i].b, p-t[i].b)<=0 ) ans ++;
138     }
139     for(int i=0;i<cntR;i++)
140     {
141         if(x>=r[i].a.x&&x<=r[i].b.x && y>=r[i].a.y&&y<=r[i].b.y) ans ++;
142     }
143     return ans;
144 }
145 
146 int main()
147 {
148     char ch;double x, y, rr;
149     while(~scanf("%d%*c", &S))
150     {
151         cntT = cntC = cntR = 0;
152         for(int i=0;i<S;i++)
153         {
154             scanf("%c", &ch);
155             if(ch == ‘C‘)
156             {
157                 scanf("%lf %lf %lf%*c", &x, &y, &rr);
158                 c[cntC++] = Circle(Point(x, y), rr);
159                 continue;
160             }
161             else if(ch == ‘T‘)
162             {
163                 Point aa[3];
164                 for(int j=0;j<3;j++)
165                 {
166                     scanf("%lf%*c%lf%*c", &x, &y);
167                     aa[j] = Point(x, y);
168                 }
169                 t[cntT++] = T(aa[0],aa[1],aa[2]);
170             }
171             else
172             {
173                 Point aa[2];
174                 for(int j=0;j<2;j++)
175                 {
176                     scanf("%lf%*c%lf%*c", &x, &y);
177                     aa[j] = Point(x, y);
178                 }
179                 r[cntR++] = R(aa[0], aa[1]);
180             }
181         }
182         scanf("%d", &N);
183         for(int i=0;i<N;i++)
184         {
185             int cntA = 0, cntB = 0;
186             for(int j=0;j<3;j++)
187             {
188                 scanf("%lf %lf", &x, &y);
189                 cntA += calc(x, y);
190             }
191             for(int j=0;j<3;j++)
192             {
193                 scanf("%lf %lf", &x, &y);
194                 cntB += calc(x, y);
195             }
196 //            printf("%d %d\n", cntA, cntB);
197             printf("%s\n", cntA > cntB ? "Bob" : (cntA == cntB ? "Tied" : "Hannah"));
198         }
199     }
200     return 0;
201 }