标签：its serial fonts 翻转 word targe level etc tween
Given a binary tree, return the zigzag level order traversal of its nodes‘ values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree {3,9,20,#,#,15,7},
3
/ 9 20
/ 15 7
return its zigzag level order traversal as:
[ [3], [20,9], [15,7] ]
confused what "{1,#,2,3}" means?
> read more on how binary tree is serialized on OJ.
Subscribe to see which companies asked this question
//递归方法：用一个bool记录是从左到右还是从右到左。每一层结束就翻转一下。class Solution { public: vector<vector<int>> zigzagLevelOrder(TreeNode* root) { vector<vector<int>> res; traverse(root, 1, res, true); return res; } void traverse(TreeNode* root, int level, vector<vector<int>> &res, bool left_to_right){ if (!root) return; if (level > res.size()) res.push_back(vector<int>()); if (left_to_right) res[level - 1].push_back(root->val); else res[level - 1].insert(res[level - 1].begin(), root->val); traverse(root->left, level + 1, res, !left_to_right); traverse(root->right, level + 1, res, !left_to_right); } };
LeetCode 103:Binary Tree Zigzag Level Order Traversal
标签：its serial fonts 翻转 word targe level etc tween
原文地址：http://www.cnblogs.com/mfmdaoyou/p/7401349.html
