标签:用户 cas 主菜单 imp ase 其他 case inpu size
实现菜单切换:
System.out.println("欢迎使用吃货联盟订单系统"); Scanner input = new Scanner(System.in); int num=-1//用户输入0返回主菜单,否则退出系统; bolean isExit=false//标志用户是否退出系统; do{ //显示菜单 System.out.println("********************************************"); System.out.println("1.我要订餐"); System.out.println("2.查看菜单"); System.out.println("3.签收订单"); System.out.println("4.删除订单"); System.out.println("5.我要点赞"); System.out.println("6.退出系统"); System.out.println("*******************************************"); System.out.print("请选择:"); int choose=input.nextInt(); if(!isExit){ System.out.print("输入0返回"); num=input.nextInt(); }else{ break; } }while(num==0);
定义一些变量:
String[] cai = { "红烧带鱼", "鱼香肉丝", "时令鲜蔬" };// 菜品 String[] names = new String[4];// 订餐人 int[] nums = new int[4];// 份数 int[] time = new int[4];// 时间 String[] site = new String[4];// 地址 String[] state = new String[] { "预定", "预定", "预定", "预定" };// 订单状态 double[] mond = { 38, 20, 10 };// 单价 int a = -1;// 输入0返回 int cd;// 输入菜单错误,重新选择 double[] b = new double[4];// 总金额 int[] zan = new int[3];// 点赞 int i = 0; int e = 0; int qian;
选择1:我要订餐
case 1: for (; i < names.length;) { System.out.println("****我要订单****"); System.out.println("请输入订单人姓名:");//使用数组记录订单人名称 names[i] = bdqn.next(); do { System.out.println("序号\t" + "菜单\t" + "单价" + "\t点赞"); //利用for循环输出(序号-菜单-单价-点赞) for (int j = 0; j < cai.length; j++) { System.out.println((j + 1) + "\t" + cai[j] + "\t" + mond[j] + "\t" + zan[j]); } System.out.println("请选择菜单:"); cd = bdqn.nextInt(); //判断输入的菜单数是否溢出菜单数 if (cd > 3 || cd < 1) { System.out.println("没有此菜品!请重新选择:"); } } while (cd > 3 || cd < 1); System.out.println("送餐份数:"); nums[i] = bdqn.nextInt(); do { System.out.println("请输入送餐时间(10至20点):"); time[i] = bdqn.nextInt(); //判断此时间营不营业 if (time[i] > 20 || time[i] < 10) { System.out.println("此时间不营业!请重新输入:"); } } while (time[i] > 20 || time[i] < 10); System.out.println("请输入送餐地址:"); site[i] = bdqn.next(); System.out.println("成功预定!"); System.out.println("您订的是:" + cai[i] + nums[i]); System.out.println("送餐时间:" + time[i]); //定义一个变量用来储存送餐费,然后进行判断 double song = 0; b[i] = mond[i] * nums[i] + song; if (b[i] < 50) { song = 5; } System.out.println("餐费:" + (b[i] - song) + "元,送餐费:" + song + "元,总计:" + b[i]); break; } //判断餐袋是否已满,未满再次执行时,录入第二次的订单情况 if (i >= site.length) { System.out.println("餐袋已满!"); } else { i++; } break;
选择2:查看菜袋
case 2: System.out.println("****查看餐袋****"); System.out.println("序号\t订餐人\t餐品信息\t送餐时间\t送餐地址\t总金额\t订单状态"); //利用for循环输出(序号-订单人-餐品信息-送餐时间-送餐地址-总金额-订单状态) for (int j = 0; j < i; j++) { System.out.println((j + 1) + "\t" + names[j] + "\t" + cai[j] + nums[j] + "份\t" + time[j] + "\t" + site[j] + "\t" + b[j] + "\t" + state[j]); } break;
选择3:签收订单
case 3: System.out.println("****签收订单****"); do { System.out.println("请输入您要签收的订单:"); qian = bdqn.nextInt(); //输入要签收的订单,判断订单是否存在和是否已签收,若未签则执行签收 if (e == qian) { System.out.println("订单已签收,不能再次签收!"); } else if (qian <= i) { System.out.println("签收成功!"); state[qian - 1] = "签收"; e = qian; break; } else if (qian > i) { System.out.println("没有该订单,请重新输入您要签收的订单:"); } } while (qian > i); break;
选择4:删除订单
case 4: System.out.println("***删除订单****"); System.out.println("请输入您要删除的订单:"); int c = bdqn.nextInt(); //输入要删除的订单,并判断是否签收(只有签收成功,才能执行删除,删除时所有关于订餐情况下标-1) if (c <= i) { if (state[c - 1].equals("签收")) { for (int j = c - 1; j < i; j++) { if (j + 1 > 3) {// 预防数组溢出 break; } names[j] = names[j + 1]; cai[j] = cai[j + 1]; nums[j] = nums[j + 1]; time[j] = time[j + 1]; site[j] = site[j + 1]; b[j] = b[j + 1]; state[j] = state[j + 1]; } System.out.println("删除成功!"); i--; e = 0; } else { System.out.println("您选择的订单,未签收,不能删除!"); } } else { System.out.println("没有此订单!"); } break;
选择5:我要点赞
case 5: System.out.println("****我要点赞****"); int l; do { System.out.println("请输入您要点赞的菜单:"); l = bdqn.nextInt(); switch (l) {// 每次选择点赞该商品+1 case 1: zan[0]++; System.out.println("点赞成功!"); break; case 2: zan[1]++; System.out.println("点赞成功!"); break; case 3: zan[2]++; System.out.println("点赞成功!"); break; default: System.out.println("无此商品序号!"); break; } } while (l > cai.length); break;
选择6:系统退出
case 6: System.out.println("退出系统!"); break;
选择其他时,显示请重新输入:
default: System.out.println("您输入的数字没有相符合的系统,请重新选择:"); break;
吃货联盟订餐系统:(整过程)
import java.util.Scanner; public class Foodie { /** * @param args */ public static void main(String[] args) { Scanner bdqn = new Scanner(System.in); String[] cai = { "红烧带鱼", "鱼香肉丝", "时令鲜蔬" };// 菜品 String[] names = new String[4];// 订餐人 int[] nums = new int[4];// 份数 int[] time = new int[4];// 时间 String[] site = new String[4];// 地址 String[] state = new String[] { "预定", "预定", "预定", "预定" };// 订单状态 double[] mond = { 38, 20, 10 };// 单价 int a = -1;// 输入0返回 int cd;// 输入菜单错误,重新选择 double[] b = new double[4];// 总金额 int[] zan = new int[3];// 点赞 int i = 0; int e = 0; int qian; do { System.out.println("\n欢迎使用“吃货联盟订餐系统”"); System.out.println("*******************************************"); System.out.println("1.我要订餐"); System.out.println("2.查看餐袋"); System.out.println("3.签收订单"); System.out.println("4.删除订单"); System.out.println("5.我要点赞"); System.out.println("6.退出系统"); System.out.println("*******************************************"); System.out.println("请选择:"); int choose = bdqn.nextInt(); switch (choose) { case 1: for (; i < names.length;) { System.out.println("****我要订单****"); System.out.println("请输入订单人姓名:");//使用数组记录订单人名称 names[i] = bdqn.next(); do { System.out.println("序号\t" + "菜单\t" + "单价" + "\t点赞"); //利用for循环输出(序号-菜单-单价-点赞) for (int j = 0; j < cai.length; j++) { System.out.println((j + 1) + "\t" + cai[j] + "\t" + mond[j] + "\t" + zan[j]); } System.out.println("请选择菜单:"); cd = bdqn.nextInt(); //判断输入的菜单数是否溢出菜单数 if (cd > 3 || cd < 1) { System.out.println("没有此菜品!请重新选择:"); } } while (cd > 3 || cd < 1); System.out.println("送餐份数:"); nums[i] = bdqn.nextInt(); do { System.out.println("请输入送餐时间(10至20点):"); time[i] = bdqn.nextInt(); //判断此时间营不营业 if (time[i] > 20 || time[i] < 10) { System.out.println("此时间不营业!请重新输入:"); } } while (time[i] > 20 || time[i] < 10); System.out.println("请输入送餐地址:"); site[i] = bdqn.next(); System.out.println("成功预定!"); System.out.println("您订的是:" + cai[i] + nums[i]); System.out.println("送餐时间:" + time[i]); //定义一个变量用来储存送餐费,然后进行判断 double song = 0; b[i] = mond[i] * nums[i] + song; if (b[i] < 50) { song = 5; } System.out.println("餐费:" + (b[i] - song) + "元,送餐费:" + song + "元,总计:" + b[i]); break; } //判断餐袋是否已满,未满再次执行时,录入第二次的订单情况 if (i >= site.length) { System.out.println("餐袋已满!"); } else { i++; } break; case 2: System.out.println("****查看餐袋****"); System.out.println("序号\t订餐人\t餐品信息\t送餐时间\t送餐地址\t总金额\t订单状态"); //利用for循环输出(序号-订单人-餐品信息-送餐时间-送餐地址-总金额-订单状态) for (int j = 0; j < i; j++) { System.out.println((j + 1) + "\t" + names[j] + "\t" + cai[j] + nums[j] + "份\t" + time[j] + "\t" + site[j] + "\t" + b[j] + "\t" + state[j]); } break; case 3: System.out.println("****签收订单****"); do { System.out.println("请输入您要签收的订单:"); qian = bdqn.nextInt(); //输入要签收的订单,判断订单是否存在和是否已签收,若未签则执行签收 if (e == qian) { System.out.println("订单已签收,不能再次签收!"); } else if (qian <= i) { System.out.println("签收成功!"); state[qian - 1] = "签收"; e = qian; break; } else if (qian > i) { System.out.println("没有该订单,请重新输入您要签收的订单:"); } } while (qian > i); break; case 4: System.out.println("***删除订单****"); System.out.println("请输入您要删除的订单:"); int c = bdqn.nextInt(); //输入要删除的订单,并判断是否签收(只有签收成功,才能执行删除,删除时所有关于订餐情况下标-1) if (c <= i) { if (state[c - 1].equals("签收")) { for (int j = c - 1; j < i; j++) { if (j + 1 > 3) {// 预防数组溢出 break; } names[j] = names[j + 1]; cai[j] = cai[j + 1]; nums[j] = nums[j + 1]; time[j] = time[j + 1]; site[j] = site[j + 1]; b[j] = b[j + 1]; state[j] = state[j + 1]; } System.out.println("删除成功!"); i--; e = 0; } else { System.out.println("您选择的订单,未签收,不能删除!"); } } else { System.out.println("没有此订单!"); } break; case 5: System.out.println("****我要点赞****"); int l; do { System.out.println("请输入您要点赞的菜单:"); l = bdqn.nextInt(); switch (l) {// 每次选择点赞该商品+1 case 1: zan[0]++; System.out.println("点赞成功!"); break; case 2: zan[1]++; System.out.println("点赞成功!"); break; case 3: zan[2]++; System.out.println("点赞成功!"); break; default: System.out.println("无此商品序号!"); break; } } while (l > cai.length); break; case 6: System.out.println("退出系统!"); break; default: System.out.println("您输入的数字没有相符合的系统,请重新选择:"); break; } if (choose == 6) { break; } System.out.println("输入0返回:"); a = bdqn.nextInt(); } while (a == 0); } }
标签:用户 cas 主菜单 imp ase 其他 case inpu size
原文地址:http://www.cnblogs.com/fl72/p/7403713.html