标签:inf sizeof ems using tin inline mem efi class
题意:给你一张简单无向图,问你1到n的次短路。注意,可以不是简单路径。
存个次短路板子,原理还是挺简单,直接看代码吧。然后这份代码还是个fread的示例用法。
#include<cstdio> #include<queue> #include<algorithm> #include<cstring> using namespace std; const int BUF=60000000; char Buf[BUF],*buf=Buf; inline void read(int&a){for(a=0;*buf<48;buf++);while(*buf>47)a=a*10+*buf++-48;} #define N 100000+10 #define INF 1000000000000000ll typedef long long ll; typedef pair<ll, int> Point; priority_queue<Point,vector<Point>,greater<Point> >Heap; int n; ll dist[N],dist2[N]; int e,first[N],nex[N<<1],v[N<<1],w[N<<1]; void AddEdge(int U, int V,int W){ v[++e]=V; w[e]=W; nex[e]=first[U]; first[U]=e; } int m,T; int main() { int x,y,z; // freopen("1011.in","r",stdin); fread(Buf,1,BUF,stdin); read(T); for(;T;--T){ read(n); read(m); e=0; memset(first,0,sizeof(first)); for(int i=1;i<=m;++i){ read(x); read(y); read(z); AddEdge(x-1,y-1,z); AddEdge(y-1,x-1,z); } fill(dist,dist+n,INF); fill(dist2,dist2+n,INF); dist[0]=0; Heap.push(Point(0,0)); while(!Heap.empty()){ Point o=Heap.top(); Heap.pop(); int U=o.second; ll d=o.first; if(dist2[U]<d){ continue; } for(int i=first[U];i;i=nex[i]){ ll d2=d+(ll)w[i]; if(dist[v[i]]>d2){ swap(dist[v[i]],d2); Heap.push(Point(dist[v[i]],v[i])); } if(dist2[v[i]]>d2 && dist[v[i]]<d2){ dist2[v[i]]=d2; Heap.push(Point(dist2[v[i]],v[i])); } } } printf("%lld\n",dist2[n-1]); } return 0; }
【dijkstra】【次短路】【fread】hdu6181 Two Paths
标签:inf sizeof ems using tin inline mem efi class
原文地址:http://www.cnblogs.com/autsky-jadek/p/7425381.html