标签:des style http color os io ar for div
Problem Description:
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1
/ 2 5
/ \ 3 4 6
The flattened tree should look like:
1
2
3
4
5
6
If you notice carefully in the flattened tree, each node‘s right child points to the next node of a pre-order traversal.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void flatten(TreeNode *root) { if(root==NULL) return; while (root != NULL) { if (root->left != NULL) { TreeNode *p = root->left; while (p->right != NULL) <span style="font-family: Arial, Helvetica, sans-serif;">//找到左孩子的最右边节点</span> { p = p->right; } p->right = root->right; root->right = root->left; root->left = NULL; } root = root->right; } } };
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode *pre=NULL; void flatten(TreeNode *root) { if(root==NULL) return; TreeNode *lastright=root->right;//记录当前节点的右子树 if(pre) { pre->left=NULL; pre->right=root; } pre=root; flatten(root->left); flatten(lastright); } };
Flatten Binary Tree to Linked List
标签:des style http color os io ar for div
原文地址:http://blog.csdn.net/longhopefor/article/details/39084259