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C++高精度问题太蛋疼了....

Yukari‘s Birthday

18
111
1111

1 17
2 10
3 10

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>

using namespace std;

typedef long long int LL;

LL n;

LL check(LL r)
{
    LL low=2,high=n,mid,ret=-1;

    while(low<=high)
    {
        mid=(low+high)/2;

        if(((LL)(pow(mid*1.,r-1.))>n||(LL)(pow(mid*1.,r-1.))<0)
           ||(LL)(pow(mid*1.,r*1.))>n||(LL)(pow(mid*1.,r*1.))<0)
        {
            high=mid-1;
            continue;
        }

        LL temp=mid*(1-(LL)(pow(mid*1.,r*1.)))/(1-mid);

        if(temp<=n-1||temp<=n)
        {
            if(temp==n||temp==n-1) ret=mid;
            low=mid+1;
        }
        else
        {
            high=mid-1;
        }
    }

    return ret;
}

int main()
{
while(scanf("%I64d",&n)!=EOF)
{
    LL R=1,K=n-1,ans=(1LL<<60);
    for(LL r=2;r<40;r++)
    {
        LL k=check(r);
        if(k==-1) continue;
        if(ans>r*k)
        {
            R=r; K=k;
        }
    }
    printf("%I64d %I64d\n",R,K);
}
    return 0;
}

HDOJ 4430 Yukari's Birthday

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原文地址：http://blog.csdn.net/ck_boss/article/details/39106329