标签:ems scanf matrix operator 直接 efi long raft for
可知
f[i] = f[i - 1] + f[i - 2] + ... + f[i - k]
直接矩阵优化就好了
#include <cstdio> #include <cstring> #define p 7777777 #define LL long long int n, k; struct Matrix { int n, m; LL a[11][11]; Matrix() { n = m = 0; memset(a, 0, sizeof(a)); } }; inline Matrix operator * (Matrix x, Matrix y) { int i, j, k; Matrix ans; ans.n = x.n; ans.m = y.m; for(i = 1; i <= x.n; i++) for(j = 1; j <= y.m; j++) for(k = 1; k <= y.n; k++) ans.a[i][j] = (ans.a[i][j] + x.a[i][k] * y.a[k][j]) % p; return ans; } inline Matrix operator ^ (Matrix x, int y) { int i; Matrix ans; ans.n = ans.m = k; for(i = 1; i <= k; i++) ans.a[i][i] = 1; for(; y; y >>= 1) { if(y & 1) ans = x * ans; x = x * x; } return ans; } int main() { int i; Matrix ans, sum; scanf("%d %d", &k, &n); ans.m = ans.a[1][1] = 1; sum.n = sum.m = ans.n = k; for(i = 1; i <= k; i++) sum.a[1][i] = 1; for(i = 2; i <= k; i++) sum.a[i][i - 1] = 1; sum = sum ^ n; ans = sum * ans; printf("%lld\n", ans.a[1][1]); return 0; }
[Vijos1067]Warcraft III 守望者的烦恼(DP + 矩阵优化)
标签:ems scanf matrix operator 直接 efi long raft for
原文地址:http://www.cnblogs.com/zhenghaotian/p/7491002.html