标签:简单 image elf div tree node 思路 code tree 题目
这道题为简单题:
最开始我以为就只是把该节点的左右孩子的节点值做绝对值就行了,结果是它的所有左右子树的值做绝对值,利用递归就行了
1 # Definition for a binary tree node. 2 # class TreeNode(object): 3 # def __init__(self, x): 4 # self.val = x 5 # self.left = None 6 # self.right = None 7 8 class Solution(object): 9 def findTilt(self, root): 10 """ 11 :type root: TreeNode 12 :rtype: int 13 """ 14 self.sum = 0 15 16 def abc(root): 17 if not root: return 0 18 19 left = abc(root.left) 20 right = abc(root.right) 21 self.sum += abs(left - right) 22 return root.val + left + right 23 24 abc(root) 25 return self.sum
标签:简单 image elf div tree node 思路 code tree 题目
原文地址:http://www.cnblogs.com/liuxinzhi/p/7498162.html