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Add Two Numbers

时间:2014-09-07 22:19:15      阅读:280      评论:0      收藏:0      [点我收藏+]

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You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)

Output: 7 -> 0 -> 8

思路:依次将每一位相加即可。

 1 class Solution {
 2 public:
 3     ListNode *addTwoNumbers( ListNode *l1, ListNode *l2 ) {
 4         if( !l1 ) { return l2; }
 5         if( !l2 ) { return l1; }
 6         int carry = 0;
 7         ListNode guard( -1 );
 8         ListNode *node = &guard;
 9         while( l1 || l2 ) {
10             if( l1 ) { carry += l1->val; }
11             if( l2 ) { carry += l2->val; }
12             node->next = new ListNode( carry%10 );
13             node = node->next;
14             carry /= 10;
15             if( l1 ) { l1 = l1->next; }
16             if( l2 ) { l2 = l2->next; }
17         }
18         if( carry ) { node->next = new ListNode( carry ); }
19         return guard.next;
20     }
21 };

 

Add Two Numbers

标签:des   style   blog   color   io   ar   div   sp   log   

原文地址:http://www.cnblogs.com/moderate-fish/p/3960837.html

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