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HDU6197

时间:2017-09-10 21:51:20      阅读:258      评论:0      收藏:0      [点我收藏+]

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array array array

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 114    Accepted Submission(s): 65


Problem Description

One day, Kaitou Kiddo had stolen a priceless diamond ring. But detective Conan blocked Kiddo‘s path to escape from the museum. But Kiddo didn‘t want to give it back. So, Kiddo asked Conan a question. If Conan could give a right answer, Kiddo would return the ring to the museum. 
Kiddo: "I have an array A and a number k, if you can choose exactly k elements from A and erase them, then the remaining array is in non-increasing order or non-decreasing order, we say A is a magic array. Now I want you to tell me whether A is a magic array. " Conan: "emmmmm..." Now, Conan seems to be in trouble, can you help him?
 

 

Input

The first line contains an integer T indicating the total number of test cases. Each test case starts with two integers n and k in one line, then one line with n integers: A1,A2An.
1T20
1n105
0kn
1Ai105
 

 

Output

For each test case, please output "A is a magic array." if it is a magic array. Otherwise, output "A is not a magic array." (without quotes).
 

 

Sample Input

3 4 1 1 4 3 7 5 2 4 1 3 1 2 6 1 1 4 3 5 4 6
 

 

Sample Output

A is a magic array. A is a magic array. A is not a magic array.
 

 

Source

 
 1 //2017-09-10
 2 #include <cstdio>
 3 #include <cstring>
 4 #include <iostream>
 5 #include <algorithm>
 6 
 7 using namespace std;
 8 
 9 const int N = 110000;
10 int arr[N], rarr[N], n, k;
11 int dp1[N], dp2[N];
12 
13 int Search(int* dp,int len,int num){  
14     int low = 1,high = len;  
15     while(low <= high){  
16             int mid = (low + high) >> 1;  
17             if (num == dp[mid]) return mid;  
18             if (dp[mid] < num) low = mid + 1;  
19             else high = mid - 1;  
20         }  
21     return low;  
22 }  
23 
24 int main()
25 {
26     int T;
27     scanf("%d", &T);
28     while(T--){
29         scanf("%d%d", &n, &k);
30         for(int i = 1; i <= n; i++)
31               scanf("%d", &arr[i]);
32         for(int i = 1; i <= n; i++)
33               rarr[i] = arr[n-i+1];
34         int lis = 1;
35         dp1[0] = -1;
36         dp1[1] = arr[1];
37         for(int i = 1; i <= n; i++){
38             if(arr[i] > dp1[lis])
39                   dp1[++lis] = arr[i];
40             else{
41                 int pos = Search(dp1, lis, arr[i]);
42                 dp1[pos] = arr[i];
43             }
44         }
45         int lds = 1;
46         dp2[0] = -1;
47         dp2[1] = rarr[1];
48         for(int i = 1; i <= n; i++){
49             if(rarr[i] > dp2[lds])
50                   dp2[++lds] = rarr[i];
51             else{
52                 int pos = Search(dp2, lds, rarr[i]);
53                 dp2[pos] = rarr[i];
54             }
55         }
56         //printf("%d %d\n", lis, lds);
57         if(n-k <= lis || n-k <= lds)
58               printf("A is a magic array.\n");
59         else
60               printf("A is not a magic array.\n");
61     }
62 
63     return 0;
64 }

 

HDU6197

标签:magic   lease   php   nbsp   rom   path   mission   others   col   

原文地址:http://www.cnblogs.com/Penn000/p/7502249.html

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