Is Subsequence

标签：bcd   let   连续   hang   its   ret   als   short   wan   

Given a string s and a string t, check if s is subsequence of t.

You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and sis a short string (<=100).

A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not).

Example 1:
s = "abc", t = "ahbgdc"

Return true.

Example 2:
s = "axc", t = "ahbgdc"

Return false.

Follow up:
If there are lots of incoming S, say S1, S2, ... , Sk where k >= 1B, and you want to check one by one to see if T has its subsequence. In this scenario, how would you change your code?

题目的意思很明显，判断s是否是t的子序列，可以不连续但是顺序要对。当s为空时，属于t的子序列。代码如下：

class Solution(object):
    def isSubsequence(self, s, t):
        """
        :type s: str
        :type t: str
        :rtype: bool
        """
        if len(si) == 0:
            return True
        si = 0
        ti = 0
        while ti < len(t):
            if s[si] == t[ti]:
                si += 1
            if si == len(s):
                return True
            ti += 1
        return False

Is Subsequence

标签：bcd   let   连续   hang   its   ret   als   short   wan   

原文地址：http://www.cnblogs.com/nicotine1026/p/7511690.html