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Best Time to Buy and Sell Stock III

时间:2014-09-09 13:31:08      阅读:128      评论:0      收藏:0      [点我收藏+]

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Say you have an array for which the ith element is the price of a given stock on dayi.

Design an algorithm to find the maximum profit. You may complete at most two transactions.

Note:
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

答案

public class Solution {
    public int maxProfit(int[] prices)
    {
        if (prices == null || prices.length <= 1) return 0;
        int LEN=prices.length;
        int maxProfit = 0;
        int i;
        int smallPrice=prices[0];
        int maxPrice=prices[LEN-1];
        int[] profitsBy= new int[LEN+1];
        int[] profitsSince= new int[LEN+1];
        for (i = 0; i <= LEN; i++ )
        {
            profitsBy[i] = 0;
            profitsSince[i] = 0;
        }
        for (i = 1; i < LEN;i++)
        {
            smallPrice=Math.min(smallPrice, prices[i]);
            profitsBy[i]=Math.max(profitsBy[i-1], prices[i]-smallPrice);
        }
        for(i=LEN-2;i>=0;i--){
            maxPrice=Math.max(maxPrice, prices[i]);
            profitsSince[i]=Math.max(profitsSince[i+1],maxPrice-prices[i]);
        }
        for(i=0;i<LEN;i++){
            maxProfit=Math.max(maxProfit, profitsBy[i]+profitsSince[i+1]);
        }
        return maxProfit;
    }
}


Best Time to Buy and Sell Stock III

标签:des   style   blog   color   os   io   java   ar   strong   

原文地址:http://blog.csdn.net/jiewuyou/article/details/39135229

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