lintcode160- Find Minimum in Rotated Sorted Array II- medium

public class Solution {
    /*
     * @param nums: a rotated sorted array
     * @return: the minimum number in the array
     */
    public int findMin(int[] nums) {

        //返回int这里怎么处理？
        if (nums == null || nums.length == 0){
            throw new IllegalArgumentException();
        }

        int start = 0;
        int end = nums.length - 1;

        while (end > 0 && nums[end] == nums[start]){
            end--;
        }

        int cmpTarget = nums[end];

        while (start + 1 < end){
            int mid = start + (end - start) / 2;
            if (nums[mid] > cmpTarget){
                start = mid;
            } else {
                end = mid;
            }
        }

        return Math.min(nums[start], nums[end]);
    }
}