标签:instead 输入 which iss each miss while pre can
http://acm.hdu.edu.cn/showproblem.php?pid=1711
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 30591 Accepted Submission(s): 12870
1 #include<cstring> 2 #include<cstdio> 3 #include<map> 4 #include<iostream> 5 using namespace std; 6 map<int,int>M; 7 int nex[10005],l1,l2,sl; 8 int S[1000005],T[10005]; 9 int solve() 10 { 11 int i,j; 12 nex[0]=nex[1]=0; 13 for(i=1;i<l2;++i) 14 { 15 j=nex[i]; 16 while(j&&T[i]!=T[j])j=nex[j]; 17 nex[i+1]=T[i]==T[j]?j+1:0; 18 } 19 j=0; 20 for(i=0;i<l1;++i) 21 { 22 while(j&&S[i]!=T[j])j=nex[j]; 23 if(S[i]==T[j]){ 24 j++; 25 if(j==l2)return i-l2+2; 26 } 27 } 28 return -1; 29 } 30 int main() 31 { 32 int i,j,t,p,x,tmp; 33 cin>>t; 34 while(t--){p=0;M.clear(); 35 scanf("%d%d",&l1,&l2); 36 for(i=0;i<l1;++i) 37 { 38 scanf("%d",&x); 39 tmp=M[x]; 40 if(!tmp){M[x]=S[i]=++p;} 41 else S[i]=tmp; 42 } 43 for(i=0;i<l2;++i) 44 { 45 scanf("%d",&x); 46 tmp=M[x]; 47 if(!tmp){M[x]=T[i]=++p;} 48 else T[i]=tmp; 49 } 50 cout<<solve()<<endl;; 51 } 52 return 0; 53 }
标签:instead 输入 which iss each miss while pre can
原文地址:http://www.cnblogs.com/zzqc/p/7588496.html