标签:hint print def type push data bzoj tin struct
对于30%的数据,N ≤ 100;
对于60%的数据,N ≤ 1000;
对于100%的数据,N ≤ 1500,输入数据保证没有重边和自环。
#include <cstring> #include <cstdio> #include <cctype> #include <queue> #define M 1000005 #define N 1505 using namespace std; struct Edge { int x,y,z; }e[M]; int dist[2][N],D[N],nextt[M<<1],to[M<<1],head[M<<1],val[M<<1],cnt,n,m,s[3],t[3],f[N],use[M]; inline void Read(int &x) { register char ch=getchar(); for(x=0;!isdigit(ch);ch=getchar()); for(;isdigit(ch);x=x*10+ch-‘0‘,ch=getchar()); } inline void ins(int u,int v,int l) { nextt[++cnt]=head[u]; to[cnt]=v; val[cnt]=l; head[u]=cnt; } bool vis[N]; struct node { int x,y; bool operator<(node a)const { return y>a.y; } }; void dijkstra(int s,int *dis) { memset(dis,0x3f,sizeof(dist[0])); memset(vis,0,sizeof(vis)); dis[s]=0; priority_queue<node>q; q.push((node){s,dis[s]}); for(node now;!q.empty();) { now=q.top(); q.pop(); if(vis[now.x]) continue; vis[now.x]=1; for(int i=head[now.x];i;i=nextt[i]) { int v=to[i]; if(dis[v]>dis[now.x]+val[i]) { dis[v]=dis[now.x]+val[i]; q.push((node){v,dis[v]}); } } } } inline void swap(int &x,int &y) {int tmp=y;y=x;x=tmp;} inline int min(int x,int y) {return x>y?y:x;} inline int max(int x,int y) {return x>y?x:y;} void calc(int s,int t) { for(int i=1;i<=m;++i) { int x=e[i].x,y=e[i].y,z=e[i].z; if(min(dist[0][x],dist[0][y])+min(dist[1][x],dist[1][y])+z==dist[0][t]) use[i]++; } } int main(int argc,char *argv[]) { Read(n);Read(m); for(int i=1;i<=2;++i) Read(s[i]),Read(t[i]); for(int a,b,c,i=1;i<=m;++i) { Read(a);Read(b);Read(c); e[i]=(Edge){a,b,c}; ins(a,b,c); ins(b,a,c); } for(int i=1;i<=2;++i) { dijkstra(s[i],dist[0]); dijkstra(t[i],dist[1]); calc(s[i],t[i]); } memset(head,0,sizeof(head)); cnt=0; for(int i=1;i<=m;++i) { if(use[i]==2) { int x=e[i].x,y=e[i].y,z=e[i].z; if(dist[0][x]>dist[0][y]) swap(x,y); ins(x,y,z);D[y]++; } } int h=0,t=0,Que[N]; for(int i=1;i<=n;++i) if(!D[i]) Que[++t]=i; for(int now;h<t;) { now=Que[++h]; for(int i=head[now];i;i=nextt[i]) { int v=to[i]; f[v]=max(f[now]+val[i],f[v]); D[v]--; if(D[v]==0) Que[++t]=v; } } int ans=0; for(int i=1;i<=n;++i) ans=max(ans,f[i]); printf("%d\n",ans); return 0; }
BZOJ 1880: [Sdoi2009]Elaxia的路线
标签:hint print def type push data bzoj tin struct
原文地址:http://www.cnblogs.com/ruojisun/p/7594130.html