FrogJmp (Codility)

标签：style   blog   color   os   io   ar   strong   for   div   

A small frog wants to get to the other side of the road. The frog is currently located at position X and wants to get to a position greater than or equal to Y. The small frog always jumps a fixed distance, D.

Count the minimal number of jumps that the small frog must perform to reach its target.

Write a function:

int solution(int X, int Y, int D);

that, given three integers X, Y and D, returns the minimal number of jumps from position X to a position equal to or greater than Y.

For example, given:

  X = 10
  Y = 85
  D = 30

the function should return 3, because the frog will be positioned as follows:

• after the first jump, at position 10 + 30 = 40
• after the second jump, at position 10 + 30 + 30 = 70
• after the third jump, at position 10 + 30 + 30 + 30 = 100

Assume that:

• X, Y and D are integers within the range [1..1,000,000,000];
• X ≤ Y.

Complexity:

• expected worst-case time complexity is O(1);
• expected worst-case space complexity is O(1).

Solution:

int solution(int X, int Y, int D) {
    // write your code in C++11
    return (Y-X)/D+((Y-X)%D==0?0:1);
}

FrogJmp (Codility)

标签：style   blog   color   os   io   ar   strong   for   div   

原文地址：http://www.cnblogs.com/oboorange/p/3963401.html