Merge Two Binary Trees

标签：node   solution   one   start   +=   new   tar   when   str   

Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not.

The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.

Example 1:Input: 

	Tree 1                     Tree 2                  
          1                         2                             
         / \                       / \                            
        3   2                     1   3                        
       /                           \   \                      
      5                             4   7                  
Output: 
Merged tree:
	     3
	    / 	   4   5
	  / \   \ 
	 5   4   7


Note: The merging process must start from the root nodes of both trees.


Solution:

struct TreeNode
{
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode(int x) :val(x), left(NULL), right(NULL) {}
};


TreeNode* mergeTrees(TreeNode *t1, TreeNode *t2)
{
    if (t1 == NULL)
        return t2;
    if (t2 == NULL)
        return t1;
    t1->val += t2->val;
    t1->left = mergeTrees(t1->left, t2->left);
    t1->right = mergeTrees(t1->right, t2->right);
    return t1;
}

Merge Two Binary Trees

标签：node   solution   one   start   +=   new   tar   when   str   

原文地址：http://www.cnblogs.com/huangzhenxiong/p/7610968.html