码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode 143. Reorder List

时间:2017-10-06 19:37:14      阅读:151      评论:0      收藏:0      [点我收藏+]

标签:col   lte   ast   link   out   ace   ring   node   while   

Given a singly linked list LL0L1→…→Ln-1Ln,
reorder it to: L0LnL1Ln-1L2Ln-2→…

You must do this in-place without altering the nodes‘ values.

For example,
Given {1,2,3,4}, reorder it to {1,4,2,3}.

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void reorderList(ListNode *head) {
        if (!head || !head->next || !head->next->next) return;
        ListNode *fast = head;
        ListNode *slow = head;
        while (fast->next && fast->next->next) {
            slow = slow->next;
            fast = fast->next->next;        
        }
        ListNode *mid = slow->next;
        slow->next = NULL;
        ListNode *curr = mid;
        ListNode *prev = NULL;
        
        while(curr) {
            ListNode *tmp = curr->next;
            curr->next = prev;
            prev = curr;
            curr = tmp;
        }
        
        while(head && prev) {
            ListNode *next = head->next;
            head->next = prev;
            prev = prev->next;
            head->next->next = next;
            head = next;
        }        
    }    
};

 

LeetCode 143. Reorder List

标签:col   lte   ast   link   out   ace   ring   node   while   

原文地址:http://www.cnblogs.com/yuanluo/p/7631988.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!