标签:col lte ast link out ace ring node while
Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You must do this in-place without altering the nodes‘ values.
For example,
Given {1,2,3,4}
, reorder it to {1,4,2,3}
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: void reorderList(ListNode *head) { if (!head || !head->next || !head->next->next) return; ListNode *fast = head; ListNode *slow = head; while (fast->next && fast->next->next) { slow = slow->next; fast = fast->next->next; } ListNode *mid = slow->next; slow->next = NULL; ListNode *curr = mid; ListNode *prev = NULL; while(curr) { ListNode *tmp = curr->next; curr->next = prev; prev = curr; curr = tmp; } while(head && prev) { ListNode *next = head->next; head->next = prev; prev = prev->next; head->next->next = next; head = next; } } };
标签:col lte ast link out ace ring node while
原文地址:http://www.cnblogs.com/yuanluo/p/7631988.html