标签：class 不用 count void public vector 使用 利用 一个
Given a 2d grid map of ‘1‘s (land) and ‘0‘s (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.
Example 1:
11110
11010
11000
00000
Answer: 1
Example 2:
11000
11000
00100
00011
Answer: 3
寻找岛屿的个数。核心思想是利用一个visited二维数组来标志一个数（1）是否被访问过。在grid二维数组中局部使用广度优先遍历来判断并寻找岛屿。如果访问过则下次就不用将其再次计算。
class Solution { public: int numIslands(vector<vector<char>>& grid) { if (grid.empty() || grid[0].empty()) return 0; int cnt = 0; const int M = grid.size(); const int N = grid[0].size(); vector<vector<bool>> visited(M, vector<bool>(N, false)); for (int i = 0; i != M; i++) { for (int j = 0; j != N; j++) { if (!visited[i][j] && grid[i][j] == ‘1‘) { numIslandsCore(grid, visited, i, j); cnt++; } } } return cnt; } void numIslandsCore(vector<vector<char>>& grid, vector<vector<bool>>& visited, int i, int j) { if (i >= 0 && i < grid.size() && j >= 0 && j < grid[0].size() && !visited[i][j] && grid[i][j] == ‘1‘) { visited[i][j] = true; numIslandsCore(grid, visited, i - 1, j); numIslandsCore(grid, visited, i, j - 1); numIslandsCore(grid, visited, i, j + 1); numIslandsCore(grid, visited, i + 1, j); } } }; // 6 ms
标签：class 不用 count void public vector 使用 利用 一个
原文地址：http://www.cnblogs.com/immjc/p/7645106.html
