标签:需要 exit 使用 solution could remove logs tar problem
原题链接在这里:https://leetcode.com/problems/baseball-game/description/
题目:
You‘re now a baseball game point recorder.
Given a list of strings, each string can be one of the 4 following types:
Integer
(one round‘s score): Directly represents the number of points you get in this round."+"
(one round‘s score): Represents that the points you get in this round are the sum of the last two valid
round‘s points."D"
(one round‘s score): Represents that the points you get in this round are the doubled data of the last valid
round‘s points."C"
(an operation, which isn‘t a round‘s score): Represents the last valid
round‘s points you get were invalid and should be removed.Each round‘s operation is permanent and could have an impact on the round before and the round after.
You need to return the sum of the points you could get in all the rounds.
Example 1:
Input: ["5","2","C","D","+"] Output: 30 Explanation: Round 1: You could get 5 points. The sum is: 5. Round 2: You could get 2 points. The sum is: 7. Operation 1: The round 2‘s data was invalid. The sum is: 5. Round 3: You could get 10 points (the round 2‘s data has been removed). The sum is: 15. Round 4: You could get 5 + 10 = 15 points. The sum is: 30.
Example 2:
Input: ["5","-2","4","C","D","9","+","+"] Output: 27 Explanation: Round 1: You could get 5 points. The sum is: 5. Round 2: You could get -2 points. The sum is: 3. Round 3: You could get 4 points. The sum is: 7. Operation 1: The round 3‘s data is invalid. The sum is: 3. Round 4: You could get -4 points (the round 3‘s data has been removed). The sum is: -1. Round 5: You could get 9 points. The sum is: 8. Round 6: You could get -4 + 9 = 5 points. The sum is 13. Round 7: You could get 9 + 5 = 14 points. The sum is 27.
Note:
题解:
需要维护住最后两个valid的数字. 可以使用queue也可以使用stack.
Time Complexity: O(ops.length).
Space: O(ops.length).
AC Java:
1 class Solution { 2 public int calPoints(String[] ops) { 3 if(ops == null || ops.length == 0){ 4 return 0; 5 } 6 7 int res = 0; 8 LinkedList<Integer> que = new LinkedList<Integer>(); 9 for(String op : ops){ 10 if(op.equals("C")){ 11 res -= que.removeLast(); 12 }else if(op.equals("D")){ 13 que.add(que.peekLast()*2); 14 res += que.peekLast(); 15 }else if(op.equals("+")){ 16 que.add(que.peekLast() + que.get(que.size()-2)); 17 res += que.peekLast(); 18 }else{ 19 que.add(Integer.valueOf(op)); 20 res += que.peekLast(); 21 } 22 } 23 24 return res; 25 } 26 }
标签:需要 exit 使用 solution could remove logs tar problem
原文地址:http://www.cnblogs.com/Dylan-Java-NYC/p/7648517.html