标签：ack round 分享 img image line inline es2017 style
解答:
$x^3+y^3+1-3xy=(x+y+1)(x^2+y^2+1+xy-x-y)=(x+y+1)(x^2+y^2+1+xy-x-y)=\frac{1}{2}(x+y+1)[(x-y)^2+(x-1)^2+(y-1)^2]\therefore x=y=1$
标签：ack round 分享 img image line inline es2017 style
原文地址：http://www.cnblogs.com/mathstudy/p/7677151.html
