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598. Range Addition II

时间:2017-10-19 12:34:45      阅读:166      评论:0      收藏:0      [点我收藏+]

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Given an m * n matrix M initialized with all 0‘s and several update operations.

Operations are represented by a 2D array, and each operation is represented by an array with two positive integers a and b, which means M[i][j] should be added by one for all 0 <= i < a and 0 <= j < b.

You need to count and return the number of maximum integers in the matrix after performing all the operations.

Example 1:

Input: 
m = 3, n = 3
operations = [[2,2],[3,3]]
Output: 4
Explanation: 
Initially, M = 
[[0, 0, 0],
 [0, 0, 0],
 [0, 0, 0]]

After performing [2,2], M = 
[[1, 1, 0],
 [1, 1, 0],
 [0, 0, 0]]

After performing [3,3], M = 
[[2, 2, 1],
 [2, 2, 1],
 [1, 1, 1]]

So the maximum integer in M is 2, and there are four of it in M. So return 4.

Note:

    1. The range of m and n is [1,40000].
    2. The range of a is [1,m], and the range of b is [1,n].
    3. The range of operations size won‘t exceed 10,000

 

class Solution(object):
def maxCount(self, m, n, ops):
"""
:type m: int
:type n: int
:type ops: List[List[int]]
:rtype: int
"""
p = m
q = n
for i in ops:
if p>i[0]:
p = i[0]
if q>i[1]:
q = i[1]
return p*q

598. Range Addition II

标签:ons   int   you   lan   put   osi   and   ever   eve   

原文地址:http://www.cnblogs.com/bernieloveslife/p/7691434.html

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