674. Longest Continuous Increasing Subsequence

标签：rate   output   temp   ==   def   put   res   list   integer   

Given an unsorted array of integers, find the length of longest continuous increasing subsequence.

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it‘s not a continuous one where 5 and 7 are separated by 4. 

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

Note: Length of the array will not exceed 10,000.

class Solution(object):
    def findLengthOfLCIS(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        temp = 1
        result = 1
        if len(nums)==0:
            return 0
        for i in range(1,len(nums),1):
            if nums[i]>nums[i-1]:
                temp +=1
            else:
                temp = 1
            result = max(result,temp)
        return result

674. Longest Continuous Increasing Subsequence

标签：rate   output   temp   ==   def   put   res   list   integer   

原文地址：http://www.cnblogs.com/bernieloveslife/p/7692663.html