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LeetCode Longest Consecutive Sequence

时间:2014-09-11 20:41:12      阅读:111      评论:0      收藏:0      [点我收藏+]

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Given an unsorted array of integers, find the length of the longest consecutive elements sequence.

For example,
Given [100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.

Your algorithm should run in O(n) complexity.

 

由于算法复杂度是O(n) ,所以不能直接排序。可以把数组存入hashset,考察每个元素的相邻元素是否在set内,把考察过的元素删除。

 

 1 public class Solution {
 2     public int longestConsecutive(int[] num) {
 3             HashSet<Integer> hashSet;
 4         
 5             if (num.length==0) {
 6                 return 0;
 7             }
 8             if (num.length==1) {
 9                 return 1;
10             }
11             hashSet=new HashSet<>();
12             
13             for (int i = 0; i < num.length; i++) {
14                 hashSet.add(num[i]);
15             }
16             int res=1;
17             for (int i = 0; i < num.length; i++) {
18                 int tmplen=1;
19                 int tmpnum=num[i]+1;
20                 while (hashSet.contains(tmpnum)) {
21                     tmplen++;
22                     hashSet.remove(tmpnum);
23                     tmpnum++;
24                 }
25                 tmpnum=num[i]-1;
26                 while (hashSet.contains(tmpnum)) {
27                     tmplen++;
28                     hashSet.remove(tmpnum);
29                     tmpnum--;
30                 }
31                 if (tmplen>res) {
32                     res=tmplen;
33                 }
34                 
35             }
36             return res;
37     }
38 }

 

LeetCode Longest Consecutive Sequence

标签:style   blog   color   io   ar   for   div   sp   log   

原文地址:http://www.cnblogs.com/birdhack/p/3967082.html

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