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LeetCode 661. Image Smoother (图像平滑)

时间:2017-10-20 10:14:06      阅读:198      评论:0      收藏:0      [点我收藏+]

标签:lis   point   make   com   elf   any   question   需要   value   

Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.

Example 1:

Input:
[[1,1,1],
 [1,0,1],
 [1,1,1]]
Output:
[[0, 0, 0],
 [0, 0, 0],
 [0, 0, 0]]
Explanation:
For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0
For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0
For the point (1,1): floor(8/9) = floor(0.88888889) = 0

 

Note:

  1. The value in the given matrix is in the range of [0, 255].
  2. The length and width of the given matrix are in the range of [1, 150].

 

 


 

题目标签:Array

  题目给了我们一个2d M array,让我们平滑处理图片。对于每一个cell,把它更新为 以自身为中心 3x3 的平均值。

  就用常规方法做,新设一个 res[][] array,遍历M,对于每一个cell, 遍历以它为中心的3x3的cells,得到平均值,存入res。

  需要注意的就是,3x3的边界问题。

 

 

Java Solution:

Runtime beats 72.97% 

完成日期:10/19/2017

关键词:Array

关键点:处理3x3的边界问题

 1 class Solution 
 2 {
 3     public int[][] imageSmoother(int[][] M) 
 4     {
 5         int rows = M.length;
 6         int cols = M[0].length;
 7         int[][] res = new int[rows][cols];
 8         
 9         for(int i=0; i<rows; i++)
10         {
11             for(int j=0; j<cols; j++)
12             {
13                 int sum = 0;
14                 int count = 0;
15                 // sum 3x3 area and take care of the boundary
16                 for(int x=Math.max(0,i-1); x<=Math.min(rows-1, i+1); x++)
17                 {
18                     for(int y=Math.max(0, j-1); y<=Math.min(cols-1, j+1); y++)
19                     {
20                         sum += M[x][y]; // sum up cells value
21                         count++; // count cells number
22                     }
23                 }
24                 
25                 res[i][j] = sum / count; // get average value
26             }
27         }
28         
29         return res;
30     }
31 }

参考资料:N/A

 

LeetCode 题目列表 - LeetCode Questions List

 

LeetCode 661. Image Smoother (图像平滑)

标签:lis   point   make   com   elf   any   question   需要   value   

原文地址:http://www.cnblogs.com/jimmycheng/p/7697511.html

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