标签:col targe bin tps nbsp self max public pre
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______ / ___2__ ___8__ / \ / 0 _4 7 9 / 3 5
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
题目含义:给定一棵二叉树,寻找其中两个给定节点的最近公共祖先(LCA)。
1 public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) { 2 while (true) 3 { 4 if (root.val > Math.max(p.val,q.val)) root = root.left; 5 else if (root.val < Math.min(p.val,q.val)) root = root.right; 6 else break; 7 } 8 return root; 9 }
235. Lowest Common Ancestor of a Binary Search Tree
标签:col targe bin tps nbsp self max public pre
原文地址:http://www.cnblogs.com/wzj4858/p/7707222.html