第三次作业结对编程

时间：2017-10-22 23:32:31 阅读：159 评论：0 收藏：0 [点我收藏+]

标签：scan else 中英文简体 http print size 技术分享 fscanf

结对编程1 四则运算

201421122075 郭晓迪

201421122089 曾瑞

需求分析：

1、记录用户的对错总数，程序退出再启动的时候，能把以前的对错数量保存并在此基础上增量计算。

2、有计时功能，能显示用户开始答题后的消耗时间。

3、界面支持中文简体/英语，用户可以选择一种；

思维导图

1.选择语言

2.答题器

代码展示

中英文对比

char * edaanpanduan(char daan[],char * shuru,char * timu)
{
static char panduanjieguo[30];
FILE * in ,* out,* cuoti;

in=fopen("leijitimushu.txt","r");
fscanf(in,"%d,%d",&eright,&ewrong);
fclose(in);

if(strcmp(shuru,edaan)==0)
{
strcpy(panduanjieguo,"Right！");
eright++;

}
else
{
strcpy(panduanjieguo,"wrong!");
strcat(panduanjieguo,"Answer is:");
strcat(panduanjieguo,edaan);
ewrong++;
cuoti=fopen("cuotiji.txt","a");
fprintf(cuoti,"%s=%s wrong!Right answer is %s\n",timu,shuru,edaan);
fclose(cuoti);
}

out=fopen("leijitimushu.txt","w");
fprintf(out,"%d,%d",eright,ewrong);
fclose(out);

return panduanjieguo;
}

char * daanpanduan(char daan[],char * shuru,char *timu)
{
static char panduanjieguo[20];
FILE * in ,* out,* cuoti;

in=fopen("leijitimushu.txt","r");
fscanf(in,"%d,%d",&right,&wrong);
fclose(in);

if(strcmp(shuru,daan)==0)
{
strcpy(panduanjieguo,"回答正确！！！！");
right++;

}
else
{
strcpy(panduanjieguo,"错误!");
strcat(panduanjieguo,"正确答案为:");
strcat(panduanjieguo,daan);
wrong++;
cuoti=fopen("cuotiji.txt","a");
fprintf(cuoti,"%s=%s 错误！正确答案为%s\n",timu,shuru,daan);
fclose(cuoti);
}

out=fopen("leijitimushu.txt","w");
fprintf(out,"%d,%d",right,wrong);
fclose(out);

return panduanjieguo;
}

程序运行