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Can Place Flowers

时间:2017-10-24 14:10:14      阅读:152      评论:0      收藏:0      [点我收藏+]

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Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.

Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.

Example 1:

Input: flowerbed = [1,0,0,0,1], n = 1
Output: True

Example 2:

Input: flowerbed = [1,0,0,0,1], n = 2
Output: False

Note:

  1. The input array won‘t violate no-adjacent-flowers rule.
  2. The input array size is in the range of [1, 20000].
  3. n is a non-negative integer which won‘t exceed the input array size.

遍历,把能种的都种上,计数比较即可

    public boolean canPlaceFlowers(int[] flowerbed, int n) {
        int sum = 0;
           for(int i=0;i<flowerbed.length;i++) {
               if(flowerbed[i]==0) {
                   if(((i-1>=0&&flowerbed[i-1]==0)||i==0)&&((i+1<flowerbed.length&&flowerbed[i+1]==0)||i==flowerbed.length-1)){
                      flowerbed[i]=1;sum++;
                   }
               }
           }
           return sum>=n;
    }

 

Can Place Flowers

标签:note   tput   eve   flow   not   blog   turn   color   ant   

原文地址:http://www.cnblogs.com/swuwyb/p/7723023.html

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