51nod1004 n^n的末位数字

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #include<cmath>
 5 #define LL  long long 
 6 using namespace std;
 7 const LL MAXN=200000001;
 8 inline LL read()
 9 {
10     char c=getchar();LL flag=1,x=0;
11     while(c<‘0‘||c>‘9‘)    {if(c==‘-‘)    flag=-1;c=getchar();}
12     while(c>=‘0‘&&c<=‘9‘)    x=(x*10+c-48),c=getchar();    return x*flag;
13 }
14 LL a[15]={1,1,4,4,2,1,1,4,4,2};
15 LL n;
16 int main()
17 {
18     n=read();
19     LL p=n%10;
20     n=n%a[p];
21     if(n==0)
22     {
23         LL ans=1;
24         for(LL i=1;i<=a[p];i++)
25             ans=ans*p;
26         cout<<ans%10;
27     }
28     else
29     {
30         LL ans=1;
31         for(LL i=1;i<=n;i++)
32             ans=ans*p;
33         cout<<ans%10;    
34     }
35     return 0;
36 }