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Leetcode: Jump Game II

时间:2014-09-12 13:26:43      阅读:145      评论:0      收藏:0      [点我收藏+]

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Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

For example:
Given array A = [2,3,1,1,4]

The minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)
 1 public class Solution {
 2     public int jump(int[] A) {
 3        if (A == null || A.length == 1) return 0;
 4        int global = 0;
 5        int steps = 0;
 6        int lastreach = 0;
 7        for (int i=0; i<=global && i<A.length; i++) {
 8            if (i > lastreach) {
 9                steps++;
10                lastreach = global;
11            }
12            global = Math.max(A[i]+i, global);
13        }
14        if (global < A.length-1) return 0;
15        else return steps;
16     }
17 }

 

Leetcode: Jump Game II

标签:style   blog   color   io   os   ar   for   div   sp   

原文地址:http://www.cnblogs.com/EdwardLiu/p/3968161.html

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