标签:oid scanf printf bsp tom main 技术 count else
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include<memory.h> 4 5 int nCount = 0; 6 int Matrix[100][100]; 7 8 void chessBoard(int tr, int tc, int dr, int dc, int size); 9 10 int main() 11 { 12 int size,r,c,row,col; 13 memset(Matrix,0,sizeof(Matrix)); 14 printf("输入棋盘的大小(大小必须是2的n次幂):"); 15 scanf("%d",&size); 16 printf("请输入特殊方格的坐标:"); 17 scanf("%d%d",&row,&col); 18 chessBoard(0,0,row,col,size); 19 20 printf("\n"); 21 for (r = 0; r < size; r++) 22 { 23 for (c = 0; c < size; c++) 24 { 25 printf("%3d ",Matrix[r][c]); 26 } 27 printf("\n"); 28 } 29 30 return 0; 31 } 32 33 void chessBoard(int tr, int tc, int dr, int dc, int size) 34 { 35 //tr and tc represent the top left corner‘s coordinate of the matrix 36 int s,t; 37 if (1 == size) return; 38 39 s = size/2; //The number of grid the matrix‘s edge 40 t = ++ nCount; 41 42 //locate the special grid on bottom right corner 43 if (dr < tr + s && dc < tc +s) 44 { 45 chessBoard(tr,tc,dr,dc,s); 46 } 47 else 48 { 49 Matrix[tr+s-1][tc+s-1] = t; 50 chessBoard(tr,tc,tr+s-1,tc+s-1,s); 51 } 52 53 //locate the special grid on bottom left corner 54 if (dr < tr + s && dc >= tc + s ) 55 { 56 chessBoard(tr,tc+s,dr,dc,s); 57 } 58 else 59 { 60 Matrix[tr+s-1][tc+s] = t; 61 chessBoard(tr,tc+s,tr+s-1,tc+s,s); 62 } 63 64 //locate the special grid on top right corner 65 if (dr >= tr + s && dc < tc + s) 66 { 67 chessBoard(tr+s,tc,dr,dc,s); 68 } 69 else 70 { 71 Matrix[tr+s][tc+s-1] = t; 72 chessBoard(tr+s,tc,tr+s,tc+s-1,s); 73 } 74 75 //locate the special grid on top left corner 76 if (dr >= tr + s && dc >= tc + s) 77 { 78 chessBoard(tr+s,tc+s,dr,dc,s); 79 } 80 else 81 { 82 Matrix[tr+s][tc+s] = t; 83 chessBoard(tr+s,tc+s,tr+s,tc+s,s); 84 } 85 86 }
标签:oid scanf printf bsp tom main 技术 count else
原文地址:http://www.cnblogs.com/yzq-wzsj/p/7605798.html