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Leetcode 283. Move Zeroes

时间:2017-10-28 17:36:13      阅读:160      评论:0      收藏:0      [点我收藏+]

标签:tco   分析   example   elements   ace   元素   function   div   数组元素   

Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

一题目:

Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.

二、分析

采用双指针压缩法:

把关注点放在非0元素上,而不是0。一个指针遍历数组元素,找到非零元素。一个指针记录压缩的当前位置。整体就遍历一次数据。

class Solution {
    public void moveZeroes(int[] nums) {
      int j = 0;
      for(int i=0; i<nums.length; i++) {
           if(nums[i] != 0) {
            int temp = nums[j];
            nums[j] = nums[i];
            nums[i] = temp;
            j++;
        }
      }
    }
}

 

Leetcode 283. Move Zeroes

标签:tco   分析   example   elements   ace   元素   function   div   数组元素   

原文地址:http://www.cnblogs.com/lyr2015/p/7747182.html

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