标签：pre array span with let log rate i++ blog
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.
Example 1:
Input: "Let‘s take LeetCode contest" Output: "s‘teL ekat edoCteeL tsetnoc"
Note: In the string, each word is separated by single space and there will not be any extra space in the string.
1 class Solution { 2 public String reverseWords(String s) { 3 if(s == null || s.length() == 0) 4 return s; 5 String []words = s.split(" "); 6 StringBuilder result = new StringBuilder(); 7 for(String word : words){ 8 String newWord = reverseWord(word); 9 result.append(newWord); 10 result.append(" "); 11 } 12 return result.toString().substring(0, result.toString().length() - 1); 13 } 14 private String reverseWord(String word){ 15 char []arr = word.toCharArray(); 16 for(int i = 0, j = arr.length - 1; i <= j; i++, j--){ 17 char temp = arr[i]; 18 arr[i] = arr[j]; 19 arr[j] = temp; 20 } 21 return new String(arr); 22 } 23 }
标签：pre array span with let log rate i++ blog
原文地址：http://www.cnblogs.com/luckygxf/p/7747318.html
