标签:xpl put been poi pre else moved for als
You‘re now a baseball game point recorder.
Given a list of strings, each string can be one of the 4 following types:
Integer
(one round‘s score): Directly represents the number of points you get in this round."+"
(one round‘s score): Represents that the points you get in this round are the sum of the last two valid
round‘s points."D"
(one round‘s score): Represents that the points you get in this round are the doubled data of the last valid
round‘s points."C"
(an operation, which isn‘t a round‘s score): Represents the last valid
round‘s points you get were invalid and should be removed.
Each round‘s operation is permanent and could have an impact on the round before and the round after.
You need to return the sum of the points you could get in all the rounds.
Example 1:
Input: ["5","2","C","D","+"] Output: 30 Explanation: Round 1: You could get 5 points. The sum is: 5. Round 2: You could get 2 points. The sum is: 7. Operation 1: The round 2‘s data was invalid. The sum is: 5. Round 3: You could get 10 points (the round 2‘s data has been removed). The sum is: 15. Round 4: You could get 5 + 10 = 15 points. The sum is: 30.
Example 2:
Input: ["5","-2","4","C","D","9","+","+"] Output: 27 Explanation: Round 1: You could get 5 points. The sum is: 5. Round 2: You could get -2 points. The sum is: 3. Round 3: You could get 4 points. The sum is: 7. Operation 1: The round 3‘s data is invalid. The sum is: 3. Round 4: You could get -4 points (the round 3‘s data has been removed). The sum is: -1. Round 5: You could get 9 points. The sum is: 8. Round 6: You could get -4 + 9 = 5 points. The sum is 13. Round 7: You could get 9 + 5 = 14 points. The sum is 27.
Note:
1 public int calPoints(String[] ops) { 2 if(ops == null || ops.length == 0) 3 return 0; 4 int []points = new int[ops.length]; 5 int point = -1; 6 int sum = 0; 7 for(String op : ops){ 8 if(op.equals("+")){ 9 sum = points[point] + points[point - 1]; 10 points[++ point] = sum; 11 }else if(op.equals("D")){ 12 sum = points[point] * 2; 13 points[++ point] = sum; 14 }else if(op.equals("C")){ 15 point --; 16 }else{ 17 points[++point] = Integer.parseInt(op); 18 } 19 } 20 sum = 0; 21 for(int i = 0; i <= point; i++){ 22 sum += points[i]; 23 } 24 return sum; 25 }
优化,少遍历一遍
1 public int calPoints(String[] ops) { 2 if(ops == null || ops.length == 0) 3 return 0; 4 int []points = new int[ops.length]; 5 int point = -1; 6 int sum = 0; 7 int temp = 0; 8 for(String op : ops){ 9 if(op.equals("+")){ 10 temp = points[point] + points[point - 1]; 11 points[++point] = temp; 12 sum += temp; 13 }else if(op.equals("D")){ 14 temp = points[point] * 2; 15 points[++ point] = temp; 16 sum += temp; 17 }else if(op.equals("C")){ 18 sum -= points[point]; 19 point --; 20 }else{ 21 points[++point] = Integer.parseInt(op); 22 sum += points[point]; 23 } 24 } 25 return sum; 26 }
标签:xpl put been poi pre else moved for als
原文地址:http://www.cnblogs.com/luckygxf/p/7747450.html