码迷,mamicode.com
首页 > 其他好文 > 详细

108. Convert Sorted Array to Binary Search Tree

时间:2017-10-30 14:19:29      阅读:164      评论:0      收藏:0      [点我收藏+]

标签:balance   panel   elements   style   solution   nod   length   convert   esc   

 

 

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

 

 1 class Solution {
 2     public TreeNode sortedArrayToBST(int[] nums) {
 3          return nums.length==0? null : ToBST(nums,0,nums.length-1);
 4         
 5         
 6     }
 7     public TreeNode ToBST(int[] nums,int lo,int hi) {
 8         if(lo>hi) return null;
 9          int mid = (lo+hi)/2;
10          TreeNode root = new TreeNode(nums[mid]);
11          root.left = ToBST(nums,lo,mid-1);
12          root.right = ToBST(nums,mid+1,hi);
13          
14         return root;
15         
16     }
17 }

 

108. Convert Sorted Array to Binary Search Tree

标签:balance   panel   elements   style   solution   nod   length   convert   esc   

原文地址:http://www.cnblogs.com/zle1992/p/7753369.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!