标签:find pac 枚举 ges memset 描述 span main 技术
枚举一个最小值用最小生成树求出最小的最大值然后判断即可
#include <stdio.h> #include <string> #include <cstring> #include <algorithm> using namespace std; #define fill(x, y) memset(x, y, sizeof(x)) #define N 4001 struct edge { int x, y, w; }e[N]; int f[N]; int find(int x) { if (!f[x]) return x; f[x] = find(f[x]); return f[x]; } int cmp(edge a, edge b) { return a.w < b.w; } int main() { int T; scanf("%d", &T); while (T--) { fill(f, 0); int n, m; scanf("%d%d", &n, &m); int ans = 0x7f7f7f7f; for (int i = 1; i <= m; i++) scanf("%d%d%d", &e[i].x, &e[i].y, &e[i].w); if (m < n - 1) { printf("-1\n"); continue; } sort(e + 1, e + m + 1, cmp); for (int i = 1; i <= m; i++) { fill(f, 0); int tot = 0; int s = e[i].w; for (int j = i; j <= m; j++) { if (find(e[j].x) != find(e[j].y)) { tot++; f[find(e[j].x)] = find(e[j].y); } if (tot == n - 1) { int t = e[j].w - s; if (t < ans) ans = t; break; } if (e[j].w - s > ans) break; } } if (ans == 0x7f7f7f7f) ans = -1; printf("%d\n", ans); } }
标签:find pac 枚举 ges memset 描述 span main 技术
原文地址:http://www.cnblogs.com/nidhogg/p/7801019.html