标签:class pre name pread while sheet 简单题 memcpy names
简单题,算法入门书上的例题,代码如下:
#include <iostream> #include <cstring> #include <cstdio> using namespace std; #define maxd 100 #define BIG 10000 int r,c,n,d[maxd][maxd],d2[maxd][maxd],ans[maxd][maxd],cols[maxd]; void copy(char type,int p,int q) { if(type==‘R‘){ for(int i = 1;i<=c;i++) d[p][i]=d2[q][i]; }else { for(int i=1;i<=r;i++) d[i][p]=d2[i][q]; } } void del(char type) { memcpy(d2,d,sizeof(d)); int cnt = type == ‘R‘ ? r:c,cnt2=0; for(int i = 1;i <= cnt; i++){ if(!cols[i])copy(type,++cnt2,i); } if(type==‘R‘)r=cnt2;else c=cnt2; } void ins(char type){ memcpy(d2,d,sizeof(d)); int cnt = type == ‘R‘?r:c,cnt2=0; for(int i = 1; i <= cnt; i++){ if(cols[i])copy(type, ++cnt2, 0); copy(type, ++cnt2, i); } if(type == ‘R‘)r = cnt2; else c = cnt2; } int main() { int r1, c1, r2, c2, q, kase = 0; char cmd[10]; memset(d, 0, sizeof(d)); while(cin>>r>>c>>n&&r){ int r0 = r, c0 = c; for(int i = 1; i <= r; i++) for(int j = 1; j <= c; j++) d[i][j] = i*BIG + j; while(n--){ cin>>cmd; if(cmd[0] == ‘E‘){ cin>>r1>>c1>>r2>>c2; int t = d[r1][c1]; d[r1][c1] = d[r2][c2]; d[r2][c2] = t; }else { int a, x; cin>>a; memset(cols, 0, sizeof(cols)); for(int i = 0; i < a; i++){ cin>>x; cols[x] = 1; } if(cmd[0] == ‘D‘) del(cmd[1]); else ins(cmd[1]); } } memset(ans, 0, sizeof(ans)); for(int i = 1; i <= r; i++) for(int j = 1; j <= c; j++){ ans[d[i][j]/BIG][d[i][j]%BIG] = i*BIG + j; } if(kase > 0)cout<<endl; cout<<"Spreadsheet #"<<++kase<<endl; cin>>q; while(q--){ cin>>r1>>c1; cout<<"Cell data in ("<<r1<<","<<c1<<") "; if(ans[r1][c1] == 0)cout<<"GONE"<<endl; else cout<<"moved to ("<<ans[r1][c1]/BIG<<","<<ans[r1][c1]%BIG<<")\n"; } } return 0; }
标签:class pre name pread while sheet 简单题 memcpy names
原文地址:http://www.cnblogs.com/ArvinShaffer/p/7800962.html